http://www.chem-toddler.com/chemical-equilibrium/chromatedichromate.html http://ibchem.com/IB/ibnotes/full/aab_htm/18.3.htm

In the try things out part (i) (a), the solid copper(II) nitrate can be used to dissolve in a test out tube filled with half distilled water. The solid copper(II) nitrate ionize in water to form copper(II) ions and nitrate ion. Hence, a blue answer is formed due to the blue copper(II) ion within the solution. Once excess stable is added, the solution can become saturated , nor allow virtually any solid to dissolve, therefore excess sturdy will remain inside the solution. This can be shows that the equilibrium among solid and aqueous copper(II) nitrate can be achieved. When the test tube is being put into the water shower of sixty, the level of solid copper(II) nitrate tends to reduce to ionize in the option but the green intensity with the solution continues to be the same. The dissolution of copper(II) nitrate is an endothermic effect. So , the equilibrium constant of the effect increases because the heat of the solution increases which will allow more products will be formed. The equilibrium location is move to the left in the equilibrium equation below: Cu(NO3)2 (aq) Cu2+ (aq) & NO3- (aq)

Eventually, even more copper(II) ions and nitrate ion are formed at the high temperature as a result of equilibrium result. Oppositely, the degree of solid copper(II) nitrate is definitely increases at the 0. When the test conduit is placed within an ice shower, the low temperature causes the equilibrium regular of the option decreases thus the formation of solid copper(II) nitrate is usually increases. The equilibrium situation shifts to the left at the condition of 0. Next, the cobalt(II) chloride can be added with hydrochloric acid in this test in order to investigate its balance at different temperature. The cobalt (II) chloride is definitely added with hydrochloric chemical p, which a pink answer is formed. When the test tube is placed in a water shower with 62, the solution turns from mild pink to dark pink. This is...

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